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Find the potential difference (in V) between points A and B shown in the figure circuit.

Option: 1

1 V


Option: 2

3 V


Option: 3

5 V


Option: 4

6 V


Answers (1)

best_answer

9V and 16\; \Omega can be ignored because potential difference between A and C is fixed, which is 4V. The circuit can be drawn as follows:

Equivalent emf is e=\frac{\Sigma(E / r)}{\Sigma(1 / r)}=\frac{10 / 2+4 / 2}{1 / 2+1 / 2}=7 \mathrm{~V}

Equivalent internal resistance is r_0=\frac{1}{\Sigma(1 / r)}=\frac{1}{1 / 2+1 / 2}=1 \Omega

Now \mathrm{V}_{\mathrm{AB}}=\frac{7}{(6+1)} \times 6=6 \mathrm{~V}

Posted by

Pankaj

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