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Find the truth table for the function \mathrm{Y}$ of $\mathrm{A}$ and $\mathrm{B} represented in the following figure.

Option: 1 \begin{array}{|c|c|c|} \hline \mathrm{A} & \mathrm{B} & \mathrm{Y} \\ \hline 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \hline \end{array}
Option: 2 \begin{tabular}{|c|c|c|} \hline $\mathrm{A}$ & $\mathrm{B}$ & $\mathrm{Y}$ \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{tabular}
 
Option: 3 \begin{tabular}{|c|c|c|} \hline $\mathrm{A}$ & $\mathrm{B}$ & $\mathrm{Y}$ \\ \hline 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \\ \hline \end{tabular}
 
Option: 4 \begin{tabular}{|c|c|c|} \hline $\mathrm{A}$ & $\mathrm{B}$ & $\mathrm{Y}$ \\ \hline 0 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{tabular}

Answers (1)

best_answer

Y=A \cdot B+\bar{B}

\begin{array}{|c|c|c|} \hline A & B & Y=A \cdot B+\bar{B} \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}

The correct option is (2)

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