Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • first overtone frequency of a closed organ pipe is equal to the fine overtone frequency of an open organ pipe. Further <img alt="\mathrm{ n^{t h}}" src="https://entrancecorner.oncodecogs.com/gif.la

first overtone frequency of a closed organ pipe is equal to the fine overtone frequency of an open organ pipe. Further \mathrm{ n^{t h}} harmonic of closed organ pipe is also equal to the \mathrm{m^{\text {th }}} harmonic of open pipe, where \mathrm{n \: \: and \: \: m} are-
 

Option: 1

5,4


Option: 2

7,5


Option: 3

9,6


Option: 4

7,3


Answers (1)

best_answer

Given, \mathrm{3\left(\frac{V}{4 l_c}\right)=2\left(\frac{V}{2 l_0}\right)}

\mathrm{\frac{l_c}{l_0}=\frac{3}{4}}

Now, \mathrm{n\left(\frac{v}{4 l_c}\right)=m\left(\frac{v}{2 l_0}\right)}

         \mathrm{\frac{n}{m}=\frac{2 l_c}{l_0}=2 \times \frac{3}{4}=\frac{3}{2} }

Thus ratio of \mathrm{\frac{n}{m}} should be \mathrm{\frac{3}{2} \: but \: n}is only odd, while in may be even or odd.

Hence option 3 is correct.

Posted by

Devendra Khairwa

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question