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  • first overtone frequency of a closed organ pipe is equal to the fine overtone frequency of an open organ pipe. Further <img alt="\mathrm{ n^{t h}}" src="https://entrancecorner.oncodecogs.com/gif.la

first overtone frequency of a closed organ pipe is equal to the fine overtone frequency of an open organ pipe. Further \mathrm{ n^{t h}} harmonic of closed organ pipe is also equal to the \mathrm{m^{\text {th }}} harmonic of open pipe, where \mathrm{n \: \: and \: \: m} are-
 

Option: 1

5,4


Option: 2

7,5


Option: 3

9,6


Option: 4

7,3


Answers (1)

best_answer

Given, \mathrm{3\left(\frac{V}{4 l_c}\right)=2\left(\frac{V}{2 l_0}\right)}

\mathrm{\frac{l_c}{l_0}=\frac{3}{4}}

Now, \mathrm{n\left(\frac{v}{4 l_c}\right)=m\left(\frac{v}{2 l_0}\right)}

         \mathrm{\frac{n}{m}=\frac{2 l_c}{l_0}=2 \times \frac{3}{4}=\frac{3}{2} }

Thus ratio of \mathrm{\frac{n}{m}} should be \mathrm{\frac{3}{2} \: but \: n}is only odd, while in may be even or odd.

Hence option 3 is correct.

Posted by

Devendra Khairwa

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