Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For 1D motion the force F(x) and the potential energy U(x) are related as:Option: 1 <img alt="F(x)=\frac{-d U(x)}{d x}" src="http

For 1D motion the force F(x) and the potential energy U(x) are related as:

Option: 1

F(x)=\frac{-d U(x)}{d x}

 

 


Option: 2

F(x)=\frac{d U(x)}{dx}

 


Option: 3

U(x)=\frac{d F(x)}{d x}

 


Option: 4

U(x)=\frac{- d F (x)}{d x}


Answers (1)

best_answer

The potential energy is equal to negative work done in shifting an object from some reference point to a given position for conservative forces.

In mathematical form, it is given as:

d U(x)=-F(x) d x \\\\ \therefore F(x)=\frac{-d U(x)}{d x}
Where F is the force in newton and dU/dx is change in potential energy.

Posted by

jitender.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question