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For a certain organ pipe, the first three resonance frequencies are in the ratio of 1 : 3 : 5 respectively. If the frequency of fifth harmonic is 405 Hz and the speed of sound in air is 324 ms^{-1} the length of the organ pipe is ______m

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Resonance frequency in closed organ pipe

$$ \mathrm{f}=(2 \mathrm{n}+1) \frac{V}{4 \ell}
Given is 5^{\text {th }} harmonic
$$ \begin{aligned} & \text { So } 5 \frac{\mathrm{V}}{4 \ell}=405 \\ & \frac{5 \times 324}{4 \times 405}=\ell \\ & \ell=1 \mathrm{~m} \end{aligned}

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