Get Answers to all your Questions

header-bg qa

For a chemical reaction \mathrm{ A+2 B \rightarrow C+2 D} , the initial rate  \mathrm{ -\frac{d[A]}{d t} } at  \mathrm{t=0 } is experimentally found to be  \mathrm{2.5 \times 10^{-2} \mathrm{M} \mathrm{s}^{-1} }
What is the value of \mathrm{-\frac{d[B]}{d t} }  at \mathrm{ t=0 } in  \mathrm{ \mathrm{M} \mathrm{s}^{-1} } ?

Option: 1

2.5 \times 10^{-2}


Option: 2

5.0 \times 10^{-2}


Option: 3

1.25 \times 10^{-2}


Option: 4

None of the above


Answers (1)

best_answer

For a reaction,  \mathrm{ a A+b B \rightarrow Products}
We know, rate of reaction at any given time \mathrm{ =-\frac{1}{a} x \frac{d[A]}{d t}=-\frac{1}{b} x \frac{d[B]}{d t}}


Hence,       \mathrm{\frac{d[B]}{d t}=\frac{b}{a} x \frac{d[A]}{d t}=2 \frac{d[A]}{d t}

                            \mathrm{=2 \times 2.5 \times 10^{-2} \mathrm{M} \mathrm{s}^{-1}=5 \times 10^{-2} \mathrm{M} \mathrm{s}^{-1}}.

Posted by

sudhir.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE