Get Answers to all your Questions

header-bg qa

For a chemical reaction \mathrm{P \rightarrow Q} it was found that concentration of Q is increased by \mathrm{0.4 \mathrm{~mol} L^{-1} } in 30 min. The average rate of the reaction is _ \mathrm{m o l L^{-1}H^{-1}}

Option: 1

6 \times 10^{-6} \mathrm{~mol} / \mathrm{L} \times \mathrm{hr}


Option: 2

9 \times 10^{-5} \mathrm{~mol} / \mathrm{L} \times \mathrm{hr}


Option: 3

8 \times 10^{-1} \mathrm{~mol} / \mathrm{L} \times \mathrm{hr}


Option: 4

3 \times 10^{-1} \mathrm{~mol} / \mathrm{L} \times \mathrm{hr}


Answers (1)

best_answer

\mathrm{\begin{aligned} & P \rightarrow Q \\ & t=00 \\ & t=30 \text { min } \quad 0.4 M \end{aligned}}

 Av. rate of reaction 

\mathrm{\begin{aligned} =-\frac{\Delta[A]}{\Delta t} & =\frac{\Delta[B]}{\Delta t}=\frac{(0.4-0)}{\frac{1}{2}} \\ =0.8 & =8 \times 10^{-1} \mathrm{~mol} / \mathrm{L} \times \mathrm{hr} \end{aligned}}

Posted by

Shailly goel

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE