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  • For a constant collector-emitter voltage of , the collector current of a transistor reached

For a constant collector-emitter voltage of 8 \mathrm{~V}, the collector current of a transistor reached to the value of 6 \mathrm{~mA} from 4 \mathrm{~mA}, whereas base current changed from 20 \mu \mathrm{A} \: to \: 25 \mu \mathrm{A} value. If transistor is in active state, small signal current gain (current amplification factor) will be :
 

Option: 1

240


Option: 2

400


Option: 3

0.0025


Option: 4

200


Answers (1)

best_answer

\mathrm{V_{c c} =8 \mathrm{~V} }

\mathrm{\Delta i_c =6 \mathrm{~mA}-4 \mathrm{~mA}=2 \mathrm{~mA} }

\mathrm{\Delta i_b=25 \mathrm{\mu A}-20 \mu \mathrm{A}-5 \mu \mathrm{A} }

\mathrm{\text { current gain }=\beta_{a c} =\frac{\Delta i c}{\Delta i_b} }

                        \mathrm{=\frac{2 \times 10^{-3}}{5 \times 10^{-6}} }
                        \mathrm{=400}

Hence 2 is correct option.



 

Posted by

Ritika Kankaria

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