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For a first order reaction, calculate the ratio between the time taken to complete 3/4 th of the reaction and time taken to complete half of the reaction?
Option: 1
4/3

Option: 2
8/3

Option: 3
2

Option: 4
1

Answers (1)

best_answer

$t_{1 / 2}=\frac{0.69}{k}, \quad t_{3/4}=t_{75 \%}$
$t_{3 / 4}=\frac{2.303}{k} \log \frac{a}{\left(a-\frac{3 a}{4}\right)}$
$\begin{array}{l}{=\frac{2.303}{k} \log 4} \\\\ {=\frac{2.303}{k} \times 2 \times 0.3010=\frac{0.69 \times 2}{k}}\end{array}$
$\frac{t_{3 / 4}}{t_{1 / 2}}=\frac{0.69 \times 2}{k} \times \frac{k}{0.69}$
$\frac{t_{3 / 4}}{t_{1 / 2}}= 2$

Therefore, option(3) is correct

Posted by

Devendra Khairwa

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