Get Answers to all your Questions

header-bg qa

For a first order reaction, the ratio of the time for 65% completion of a reaction to the time for 50% completion is

Option: 1

2.841


Option: 2

1.5152


Option: 3

3.692


Option: 4

4.662


Answers (1)

best_answer

\mathrm{T=\frac{2.303}{k} \log \left(\frac{100}{100-x \%}\right)}

\mathrm{T_{65 \%}=\frac{2.303}{k} \log \left(\frac{100}{35}\right)}

\mathrm{T_{50 \%}=\frac{2.303}{k} \log \left(\frac{100}{50}\right)}

\mathrm{\frac{T_{65 \%}}{T_{50 \%}}=1.5152}

Posted by

jitender.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE