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  • For a hypothetical H like atom which follows Bohr’s model, some spectral lines were observed as shown. If it is known that line ‘E’ belongs to the visible region, then the lines p

For a hypothetical H like atom which follows Bohr’s model, some spectral lines were observed as shown. If it is known that line ‘E’ belongs to the visible region, then the lines possibly belonging to the ultraviolet region will be (n1 is not necessarily ground state)

     [Assume for this atom, no spectral series shows overlaps with other series in the emission spectrum]

Option: 1

B and D


Option: 2

 D only


Option: 3

C only


Option: 4

A only


Answers (1)

best_answer

 

Bohr’s Model for Hydrogen Atom/Hydrogen like atoms -

Bohr's model :

1. Force of attraction between the nucleus and an electron is equal to centripetal force.

2. mv r= nh/2\pi ,  n = principal quantum number.

3. Energy can be absorbed or emitted when electron transfer orbit  E_{1}-E{_{2}}=h\nu

E2 is higher energy state and E1 is lower energy state

-

Balmer Series Spectrum -

\frac{1}{\lambda }= RZ^{2}\left ( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right )

Where n_{1}=2\ and\ n_{2}=3, 4, 5, 6 .....

It lies in the visible region

-

In the given figure if line ‘E’ is in the visible region then line belonging to the ultraviolet region will have more energy than ‘E’ i.e. line A.

For the line in UV region, the energy must be more than that corresponding to E.

The energy of A > Energy of E.

Hence, the option number (4) is correct.

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