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  • For a particular reaction, Rate constant . The initial concen

For a particular reaction, Rate constant \mathrm{ k=2.3038^{-1}}. The initial concentration of the reactant is \mathrm{2 \mathrm{~mol}~ L^{-1}}  then rate of reaction after 1 second will be:

 

Option: 1

0.2303 \mathrm{Ms}^{-1}


Option: 2

0.4606 \mathrm{Ms}^{-1}


Option: 3

2.303 \mathrm{~ms}^1


Option: 4

4.606 \mathrm{~ms}^{-1}


Answers (1)

best_answer

\begin{aligned} &\mathrm{ k=\frac{2.303}{t} \log \frac{[R]_0}{[R]} \quad \begin{array}{ll} \end{array} }\\ &\mathrm{ 2.303=\frac{2.303}{1} \log \frac{2}{[R]} \quad }\\ &\mathrm{ \frac{2}{[R]}=10 \quad }\\ &\mathrm{ [R]=0.2 \text { Rate after } 1 }\\ &\mathrm{\gamma_1=k[R]=2.303 \times 0.2=0.4606 \mathrm{~ms}^{-1}}\\ \end{aligned}

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