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For a plane electromagnetic wave, the magnetic field at a point x and time t is : \vec{B}(x,t)=\left [ 1.2\times10^{-7}\; \sin(0.5\times10^{3}x+1.5\times10^{11}t)\hat{k} \right ]T The instantaneous electric field \vec{E} corresponding to \vec{B} is : (speed of light c=3\times10^{8}\; ms^{-1})
Option: 1 \vec{E}(x,t)=\left [ -36\; \sin(0.5\times10^{3}x+1.5\times10^{11}t)\hat{j} \right ]\frac{V}{m}
Option: 2 \vec{E}(x,t)=\left [ 36\; \sin(1\times10^{3}x+0.5\times10^{11}t)\hat{j} \right ]\frac{V}{m}
Option: 3 \vec{E}(x,t)=\left [ 36\; \sin(0.5\times10^{3}x+1.5\times10^{11}t)\hat{k} \right ]\frac{V}{m}
Option: 4 \vec{E}(x,t)=\left [ 36\; \sin(1\times10^{3}x+1.5\times10^{11}t)\hat{i} \right ]\frac{V}{m}

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\vec{B}=1.2 \times 10^{-7} \sin \left(0.5 \times 10^{3} x+1.5 \times 10^{11} t\right) \hat{k} T$ \\ Wave is travelling along $-x$ axis and $\vec{B}$ is along +z axis. \\ $E_{0}=c B_{0}=36 \frac{v}{m}$ \\ $\overrightarrow{\mathrm{E}}$ must be along $-\mathrm{y}$ axis

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Deependra Verma

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