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For a reaction, A \rightarrow B it has been found that the order of the reaction is zero with respect to A. Which of the following expression correctly describes the reaction?

Option: 1

\mathrm{k}=\frac{2.303}{\mathrm{t}} \log \frac{\left[\mathrm{A]}_{0}\right.}{[\mathrm{A}]}


Option: 2

\left[\mathrm{A]}_{0}-[\mathrm{A}]=\mathrm{kt}\right.


Option: 3

\mathrm{t_{1 / 2}=\frac{0.693}{k}}


Option: 4

\mathrm{t}_{1 / 2} \propto \frac{1}{[\mathrm{A}]_{0}}


Answers (1)

best_answer

For a reaction, A \rightarrow B it has been found that the order of the reaction is zero with respect to A.

\\ -\frac{\mathrm{d}[\mathrm{A}]}{\mathrm{dt}}=\mathrm{k}[\mathrm{A}]^{0}\\\\-\mathrm{d}[\mathrm{A}]=\mathrm{kdt} \\\\ \text {Integrating from } \mathrm{t}=0 \text { to } \mathrm{t}=\mathrm{t} \\ \\\ [ \mathrm{A} ]_0 - [ \mathrm{A} ] = \mathrm{kt}

Therefore, option(2) is correct

Posted by

Devendra Khairwa

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