Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For a reaction, given below is the graph of  <img alt="\ln \mathrm{kvs} \frac{1}{\mathrm{~T}}." src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cln%20%5Cmathrm%7Bkvs%7D%20%5Cfrac%7B1%7D

For a reaction, given below is the graph of  \ln \mathrm{kvs} \frac{1}{\mathrm{~T}}. The activation energy for the reaction is equal to________ \mathrm{cal \: \: \mathrm{mol}^{-1}}. (nearest integer)
(Given : \mathrm{R}=2 \mathrm{cal} \mathrm{K}^{-1} \mathrm{~mol}^{-1} )

Option: 1

8


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer



\mathrm{K= Ae^{-Ea/RT}}
\mathrm{ln\, K= ln\, A-\frac{Ea}{RT}}

\mathrm{slope= \frac{Ea}{R}= \frac{20}{5}}

\mathrm{Ea= 4R= 8Cal/mol.}

Hence answer is 8

Posted by

Ritika Harsh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Maharashtra to introduce policy for regulating coaching centres: Report
anam-khan

JEE Main 2026: BTech civil engineering cut-offs at NITs show steady demand after years of decline
anam-khan

JEE Main 2026 Registration LIVE: NTA to close applications on November 27, revises session 2 exam dates

Latest Question