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  • For a reaction <img alt="\mathrm{ \mathrm{A} \rightarrow 2 \mathrm{~B}+\mathrm{C}}" src="/latex-image/?%5Cmathrm%7B%20%5Cmathrm%7BA%7D%20%5Crightarrow%202%20%5Cmathrm%7B%7EB%7D&plus;%5Cmat

For a reaction \mathrm{ \mathrm{A} \rightarrow 2 \mathrm{~B}+\mathrm{C}} the half lives are \mathrm{100 \mathrm{~s}} and \mathrm{50 \mathrm{~s}} when the concentration of reactant \mathrm{ A}  is \mathrm{ 0.5} and \mathrm{1.0 \mathrm{~mol} \mathrm{~L}-1}  respectively. The order of the reaction is _____________. (Nearest Integer)

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

The half life depends on concentration raise to power \mathrm{(1-n)} where n is order \mathrm{t_{1 / 2}\; \alpha, a^{(1-m)}}

\mathrm{\begin{aligned} &\frac{\left(t_{112}\right)_1}{\left(t_{1 / 2}\right)_2}=\left(\frac{a_1}{a_2}\right)^{1-n} \\ &\frac{100}{50}=\left(\frac{0.5}{1}\right)^{1-n} \end{aligned}}

\mathrm{2^{1}=2^{n-1}}                       \mathrm{n-1=1\; \; \; \; \; \; n=2}

Order of reaction is 2

Answer is 2

Posted by

HARSH KANKARIA

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