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For a reaction:
\mathrm{3A\rightarrow products}
It is found that the rate of reaction doubles when the concentration of A is increased by four times. What is the order of the reaction?

 

Option: 1

1


Option: 2

1 / 2 \\


Option: 3

3 / 2 \\


Option: 4

2


Answers (1)

best_answer

Rate \mathrm{=k[\text { Reactant }]^n}
Here:
\mathrm{ r_1=k[A]^n \ldots \ldots \ldots \\ }(1)

\mathrm{ r_2=2 r_1=k[4 A]^n }..............(2)

where \mathrm{ r_1 } is the rate of the reaction
Now dividing equation (2) by equation (1), we get,

\mathrm{ 2=[4]^n \\ }

\mathrm{ \Rightarrow n=\frac{1}{2} }.
 

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chirag

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