Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

For an elementary reaction \mathrm{2 X+Y \rightarrow X_2 Y}. If the volume of the container is quickly deceased to 50 % of its original volume, then rate of reaction will
 

Option: 1

 remain same
 


Option: 2

 increase 400 %

 


Option: 3

 increase to 800 %

 


Option: 4

 decrease by 800 %


Answers (1)

best_answer

Rate =\mathrm{k[X]^2[Y] } { By halving volume, conc. doubles}

\begin{aligned} & \text { Rate }_2=\mathrm{k[2 X]^2[2 Y]} \\ & \text { Rate }_2=\mathrm{8 k[X]^2[Y]=8 \text { Rate }_1=800 \% \text { Rate }_1} \end{aligned}

Posted by

Gautam harsolia

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

BTech aspirant from north-east or UT? Apply for CSAB NEUT counselling 2025 today
anam-khan

JoSAA round 2 cut-off 2025 out; BTech closing ranks for top engineering courses at IITs
anam-khan

Goa Engineering Admission 2025: 1,415 eligible for BE seats; merit list on June 27

Latest Question