Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For an ideal-gas reaction  <img alt="2 \mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}" src="http://entrancecorner.oncodecogs.com/gif.latex?2%20%5Cmathrm%7BA%7D&plus;%5

For an ideal-gas reaction  2 \mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D} , the value of Kp will be:

(Volume of container is V)

Option: 1

\mathrm{K _{p}^{o}=\frac{n_C \times n_{ D }}{n_A^{2} \times n_{ B }} \left (\frac{V}{R T^{2}} \right )}


Option: 2

\mathrm{K _{p}^{o}=\frac{n_C \times n_{ D }}{n_A^{2} \times n_{ B }} \left (\frac{P}{R T} \right )}


Option: 3

\mathrm{K _{p}^{o}=\frac{n_C \times n_{ D }}{n_A^{2} \times n_{ B }} \left (\frac{R T^{2}}{V} \right )}


Option: 4

\mathrm{K _{p}^{o}=\frac{n_C \times n_{ D }}{n_A^{2} \times n_{ B }} \left (\frac{V}{RT} \right )}


Answers (1)

best_answer

\text { Reaction: } 2 \mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}

\mathrm{K_P = \frac{P_C \times P_D}{P_A^2 \times P_B}}

\mathrm{K_P = \frac{n_C \times n_D}{n_A^2 \times n_B} \times \left ( \frac{RT}{V} \right )^{\Delta n_g}, \ \Delta n_g = -1}

\mathrm{K_P = \frac{n_C \times n_D}{n_A^2 \times n_B} \times \left ( \frac{RT}{V} \right )^{-1}}
\mathrm{K_P = \frac{n_C \times n_D}{n_A^2 \times n_B} \times \left ( \frac{V}{RT} \right )}
Therefore,option(4) is correct

Posted by

Ritika Harsh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions