Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • For reation , the value of the equilibrium constant at 300K and 1atm is equal to 100.0. The value of <img alt="\Delta_rG" s

For reation A(g)\rightarrow B(g), the value of the equilibrium constant at 300K and 1atm is equal to 100.0. The value of \Delta_rG for the reaction at 300K and 1 atm in Jmol-1 is -xR, where x is ___________(Rounded off to the nearest integer)
Option: 1 1380
Option: 2 -
Option: 3 -
Option: 4 -

Answers (1)

best_answer

We know,

\Delta \mathrm{G}^{\circ}=-\mathrm{RT} \text { In Keq. }

= -R X 300 X ln(102)

=  (-R) X 300 X 2 X ln(10)

=  (-R) X 300 X 2 X 2.3

=  -1380R

Now,

-xR = -1380R

So, x = 1380.

Posted by

sudhir.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Registration LIVE: NTA application open soon on jeemain.nta.nic.in; exam from January 21
anam-khan

JEE Main 2026: Minimum marks to secure top 1000 rank in JEE Advanced; rank vs score trend over 5 years
anam-khan

JEE Main 2026 Aadhaar Authentication: How to fix name mismatch during registration?

Latest Question