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  •  For the adsorption of hydrogen on platinum the activation energy is <img alt="22 \mathrm{~kJ} \mathrm{~mol}^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?22%20%5Cmathrm%7B%7

 For the adsorption of hydrogen on platinum the activation energy is 22 \mathrm{~kJ} \mathrm{~mol}^{-1}and for the adsorption of hydrogen on nickel, the activation energy is 55 \mathrm{~kJ} \mathrm{~mol}^{-1}. The logarithm of the ratio of the Chemisorption on equal areas of the metal at 300 \mathrm{~K} is

Option: 1

5.76
 


Option: 2

 4.28
 


Option: 3

 3.22
 


Option: 4

 2.178


Answers (1)

best_answer

According to Arrhenius is equation
\mathrm{\begin{gathered} k=A e^{-E a / R T} \\ \log k=\log A ^{\frac{-E a}{{2.3 R T}}} \end{gathered} }
\mathrm{E a_1 }= for the adsorption of hydrogen on platinum, the activation energy. 
\mathrm{E a_2 }= for the adsorption of hydrogen on nickel, the activation energy.
\mathrm{E_{a_2}-E_{a_1}=55-22=33 }
\mathrm{\begin{aligned} \log \left(\frac{k_1}{k^2}\right)=\frac{E a_2-E a_1}{2.3 R T} & =\frac{33 \times 100}{2.3 \times 8.3 \times 300} \\ & =5.76 \end{aligned} }

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