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  • For the electrical circuit shown in the figure, the potential difference across the resistor of 400  as will be mea

For the electrical circuit shown in the figure, the potential difference across the resistor of 400 \Omega as will be measured by the voltmeter V of resistance 400 is-

Option: 1


\frac{10}{3} \mathrm{V}\\

 


Option: 2

4 \mathrm{V}


Option: 3

\frac{20}{3} \mathrm{V}
 


Option: 4

5 \mathrm{V}


Answers (1)

best_answer

 

 

 

 

 

This circuit actually forms a Wheatstone bridge.

Since resistance of voltage is 400Ω, resistance viewed by voltmeter R0.

\begin{aligned} &\frac{1}{\mathrm{R}_{0}}=\frac{1}{\mathrm{R}}+\frac{1}{\mathrm{R}_{\mathrm{V}}}\\ &\mathrm{Rv}=400 \Omega, \mathrm{R}=400 \Omega\\ &\Rightarrow \mathrm{R}_{0}=200 \Omega \end{aligned}

Now we see there is a wheat stone bridge formed.

Hence, the middle $100 \Omega$ can be ignored.

\Rightarrow V_{400 \Omega}=\frac{200}{200+100} \times 10=\frac{20}{3} V$.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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Posted by

Gautam harsolia

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