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  • For the frequency distribution: Variate (x) :           

For the frequency distribution: Variate (x) : x_{1}     x_{2}      x_{3}      .....x_{15} Frequency (f):  f_{1}     f_{2}       f_{3}.......f_{15} where 0<x_{1}<x_{2}<x_{3}<............<x_{15}=10 and \sum_{i=1}^{15}f_{i}>0, the standard deviation cannont be:
Option: 1 4
Option: 2 1
Option: 3 6
Option: 4 2

Answers (1)

best_answer

\because \sigma^{2} \leq \frac{1}{4}(\mathrm{M}-\mathrm{m})^{2}

Where M and m are upper and lower bounds of values of any random variable.

\\ \because \sigma^{2} \leq \frac{1}{4}(10-0)^{2} \\ \Rightarrow 0<\sigma<5 \\ \therefore \sigma \neq 6

Posted by

Suraj Bhandari

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