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  • For the hypothetical reactions, the equilibrium constant (K) values are given: <img alt="\mathrm{A \rightleftharpoons B ; K_{1}=2 ; \quad B \rightleftharpoons C ; K_{2}=4 ;\quad C \r

For the hypothetical reactions, the equilibrium constant (K) values are given:

\mathrm{A \rightleftharpoons B ; K_{1}=2 ; \quad B \rightleftharpoons C ; K_{2}=4 ;\quad C \rightleftharpoons D ; K_{3}=3}
The equilibrium constant (K) for the reaction \mathrm{A \rightleftharpoons D} is:

Option: 1

12


Option: 2

24


Option: 3

6


Option: 4

9


Answers (1)

The required reaction \mathrm{A\rightleftharpoons D} can be obtained by adding all the given reactions

We know that the Equilibrium constants get multiplied when the equations are added

\therefore \mathrm{K = K_1 \times K_2 \times K_3}

\Rightarrow \mathrm{K = 2 \times 4 \times 3=24}


Therefore,option(2) is correct

Posted by

Ramraj Saini

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