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For the reaction \mathrm{R(g) \rightarrow P(g)}, graph drawn between \mathrm{\log \left(-\frac{d[R]}{d t}\right)} vs \mathrm{\log [R]} is given:

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


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\begin{aligned} &\mathrm{ \because \text { Rate }=-\frac{d[R]}{d t}=k[R]^n }\\ &\mathrm{ \log \left(-\frac{d[R]}{d t}\right)=\log k+n \log [R] }\\ &\mathrm{ \text { slope }=n=\tan \theta=2}\\ \end{aligned}

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Anam Khan

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