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  • For the reaction <img alt="H_{2}(g)+I_{2}(g)\leftrightharpoons 2HI(g)" src="http://entrancecorner.oncodecogs.com/gif.latex?H_%7B2%7D%28g%29&plus;I_%7B2%7D%28g%29%5Cleftrightharpoons%202HI%28g%2

For the reaction H_{2}(g)+I_{2}(g)\leftrightharpoons 2HI(g), the standard free energy is \Delta G^{0}>0. The equilibrium constant (K ) would be __________. 

Option: 1

K = 0


Option: 2

K > 1


Option: 3

 K = 1


Option: 4

K < 1


Answers (1)

best_answer

A spontaneous reaction has a negative delta G (\Delta G< 0) and a large K( K>1) value.

A non-spontaneous reaction has a positive delta G (\Delta G>0) and a small K (K<1) value.

When delta G is equal to zero (\Delta G=0) and K is around one (K=1), the reaction is at equilibrium.

This relationship allows us to relate the standard free energy change to the equilibrium constant.

Therefore, option number (4) is correct.

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