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  • For the reaction, <img alt="\mathrm{2 NO + Cl _{2} \rightarrow 2 NOCl}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2%20NO%20&plus;%20Cl%20_%7B2%7D%20%5Crightarro

For the reaction,

\mathrm{2 NO + Cl _{2} \rightarrow 2 NOCl}

it is found that doubling the concentration of both reactants increases the rate by a factor of 8, but doubling the Cl2 concentration alone, only doubles the rate. What is the order of the reaction with respect to NO and Cl2?

Option: 1

1,1


Option: 2

1,2


Option: 3

2,1


Option: 4

2,2


Answers (1)

best_answer

\mathrm{Rate = k [NO]^m [Cl_2]^n}

Given,

\mathrm{R_1 = k [NO]^m [Cl_2]^n}

\mathrm{R_2 = k 2^m[NO]^m 2^n [Cl_2]^n= 2^{m+n} R_1}

\mathrm{R_3 = k [NO]^m 2^n [Cl_2]^n= 2^{n} R_1}

According to the experimental data given,

\mathrm{2^{m+n}=8 \ and\ 2^n= 2}

Upon solving,

\mathrm{m=2,\ n= 1}

Hence, the correct answer is Option (3)

Posted by

Kuldeep Maurya

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