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From the following, the quantity (constructed from the basic constants of nature), that has the dimensions, as well as correct order of magnitude, vis-a-vis typical atomic size, is : 

Option: 1

\frac{e^2}{4\pi \epsilon_0mc^2}-


Option: 2

\frac{4\pi \epsilon_0h^2}{me^2}


Option: 3

\frac{mc^2}{4\pi \epsilon_0b^2}-


Option: 4

\frac{4\pi \epsilon_0mc^2}{e^2}


Answers (1)

The typical atomic size given by 

 

\frac{4 \pi \varepsilon_{0} h^{2}}{m e^{2}}

Posted by

Ramraj Saini

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