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  • Give answer! 4g of impure CaCO3on treatment with excess HCl produces 0.88 g CO2. What is the percent purity of CaCO3sample?

4g of impure CaCO3 on treatment with excess HCl produces 0.88 g CO2. What is the percent purity of CaCO3 sample?

  • Option 1)

    75

  • Option 2)

    25

  • Option 3)

    90

  • Option 4)

    50

 

Answers (1)

best_answer

As we learnt

 

Dalton's Atomic Theory -

Compounds are formed when atoms of different elements combine in a fixed ratio.

- wherein

N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}

Nitrogen & Hydrogen combine in a fixed ratio to yeild ammonia (compound)

 

 

Ratio of elements in CaCO3 :

Ca : 1, C : 1, O : 3

Molar mass = 1\times 40 + 1\times 12 + 3\times 16 = 100

CaCO_{3}\overset{\Delta}{\rightarrow} CaO + CO_{2}

    x                     0            0

    0                                    \frac{0.88}{44} mol

\\*\therefore x =\frac{0.88}{44} mol = 0.02 mol = 2g \\*\therefore \% purity = \frac{2}{4} \times 100 = 50

\\*\therefore Solution is D


Option 1)

75

This is  incorrect.

Option 2)

25

This is  incorrect.

Option 3)

90

This is  incorrect.

Option 4)

50

This is  correct.

Posted by

prateek

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