A circuit has a resistance of 12 ohm and an impedance of 15 ohm. The power factor of the circuit will be

  • Option 1)

    1.25

  • Option 2)

    0.125

  • Option 3)

    0.8

  • Option 4)

    0.4

 

Answers (1)

As we learnt in 

R.L Circuit Voltage -

V_{R}= IR

V_{L}= {I}X_{L}

- wherein

 

 

Power factor -

\cos \phi = \frac{R}{\sqrt{R^{2}+X_{c}^{2}}}

-

Solution is correct

Capacitive current (C) Current -

{i}'= {i}'_{0}\sin \left ( \omega t+\frac{\pi }{2} \right )

- wherein

 

 

Inductive circuit (L) Current -

{i}'= {i}'_{0}\sin \left ( \omega t-\frac{\pi }{2} \right )

- wherein

Power\; factor\; cos\phi =\frac{R}{Z}=\frac{12}{15}=0.8

 


Option 1)

1.25

This option is incorrect

Option 2)

0.125

This option is incorrect

Option 3)

0.8

This option is correct

Option 4)

0.4

This option is incorrect

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