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  • Give answer! A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of increaed length is

A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the percentage increase in the time period of the pendulum of increaed length is

  • Option 1)

    10%

  • Option 2)

    21%

  • Option 3)

    30%

  • Option 4)

    50%

 

Answers (1)

best_answer

If initial length l_{1} = 100 then l_{2} = 121

By using T = 2\pi \sqrt{\frac{l}{g}} \Rightarrow \frac{T_{1}}{T_{2}} = \sqrt{\frac{l_{1}}{l_{2}}}

Hence, \frac{T_{1}}{T_{2}} = \sqrt{\frac{100}{121}}\Rightarrow T_{2} =1.1T_{1}

% increase = \frac{T_{2} - T_{1}}{T_{1}}\times 100 = 10\%

 

Physical pendulum -

Any rigid body suspended from a fixed support constitute a physical pendulum.

- wherein

e.g.

A circular ring suspended on a nail in a wall etc.

 

 

 


Option 1)

10%

This is correct.

Option 2)

21%

This is incorrect.

Option 3)

30%

This is incorrect.

Option 4)

50%

This is incorrect.

Posted by

divya.saini

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