Get Answers to all your Questions

header-bg qa

A stretched wire has a Young’s modulus Y and energy density E. the strain in the stretched wire is

  • Option 1)

    \frac{2E}{Y}

  • Option 2)

    \frac{E}{Y}

  • Option 3)

    \sqrt{\frac{2E}{Y}}

  • Option 4)

    \sqrt \frac{E}{Y}

 

Answers (1)

As we discussed in concept

Stress -

The internal restoring force per unit area of deformed body.

- wherein

Due to the forces, the body gets deformed and internal forces appear.

 

 

Stress -

Stress =\frac{force}{Area}=\frac{F}{A}
 

- wherein

F= applied \: force

A= area \:

 

 E=\frac{1}{2}\times Stress \times Strain

E=\frac{1}{2}\times Stress \times \frac{Stress}{Y}\:=\:\frac{1}{2}\:\frac{S^{2}}{Y}

E=\frac{1}{2Y}\:Y^{2}(Strain)^{2}\:\:\:\:\:\:\:\:\:\:\:\Rightarrow 2E=YS^{2}

S=\sqrt{\frac{2E}{Y}}


Option 1)

\frac{2E}{Y}

This option is incorrect.

Option 2)

\frac{E}{Y}

This option is incorrect.

Option 3)

\sqrt{\frac{2E}{Y}}

This option is correct.

Option 4)

\sqrt \frac{E}{Y}

This option is incorrect.

Posted by

Vakul

View full answer