Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Give answer! - Complex numbers and quadratic equations - JEE Main-3

The value of 'a' for which \left ( a^{2}-1 \right )x^{2}+\left ( a^{2}-3a+2 \right )x+\left ( a^{2}-4a+3 \right )= 0 becomes a quadratic identity equals 

  • Option 1)

    -1

  • Option 2)

    0

  • Option 3)

    1

  • Option 4)

    2

 

Answers (1)

best_answer

for identity : a^{2}-1=0, \, a^{2}-3a+2=0,\, a^{2}-4a+3=0

Simultaneously.

Which is possible when a=1

\therefore Option (C)

 

Quadratic Equation become an Identity -

Satisfied by more than two values of x

\Leftrightarrow a=b=c=0

 

-

 

 


Option 1)

-1

This is incorrect

Option 2)

0

This is incorrect

Option 3)

1

This is correct

Option 4)

2

This is incorrect

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech CSE cut-offs for PwD candidates at NITs make entry easy; top institutes still selective
anam-khan

73 or 99 percentile? JEE Main result questioned, J-K candidate says, ‘Don’t create hype’
anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile

Latest Question