# Consider the LR circuit shown in the figure. If the switch S is closed at t=0 then the amount of charge that passes through the battery between $t=0$ and $t=\frac{L}{R}$ is :  Option 1)  $\frac{2.7EL}{R^{2}}$       Option 2) $\frac{EL}{2.7R^{2}}$ Option 3) $\frac{7.3EL}{R^{2}}$ Option 4) $\frac{EL}{7.3R^{2}}$

Inductance -

It is the property of electrical circuits which oppose any change in the  current in the circuits.

-

$q=\int Idt$

$I=\frac{E}{R}[1-e\frac{-Rt}{L}]$

$q=\int ^{L/R}_{o}\frac{E}{R}\left [ 1-e^{-\frac{R}{L}t}\right ]dt$

$q=\frac{EL}{R^{2}}\times \frac{1}{e}$

$\Rightarrow \frac{EL}{2.7R^{2}}$

Option 1)

$\frac{2.7EL}{R^{2}}$

Option 2)

$\frac{EL}{2.7R^{2}}$

Option 3)

$\frac{7.3EL}{R^{2}}$

Option 4)

$\frac{EL}{7.3R^{2}}$

Exams
Articles
Questions