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Fundamental frequency of sonometer wire is n. If the tension is made thee times and length and diameter are also increased by 3 times, what is the new frequency

  • Option 1)

    \frac{n}{3\sqrt3}

  • Option 2)

    3n

  • Option 3)

    \sqrt3 n

  • Option 4)

    \frac{n}{\sqrt3}

 

Answers (1)

best_answer

n= \frac{v}{2l}\sqrt{\frac{\frac{T}{M}}{2l}}= \sqrt{\frac{\frac{T}{\rho s}}{2l}}

= \sqrt{\frac{\frac{T}{\rho \pi r^{2}}}{2l}}\Rightarrow n\propto \frac{\sqrt{T}}{2l}

so n will become \frac{1}{3\sqrt{3}} times

 

Standing wave in a string fixed at both ends -

 

- wherein

\nu _{n}= \frac{n}{2L}.\sqrt{\frac{T}{\mu }}

n= 1,2,3...........

\nu _{n} frequency of nth harmonic .

T= tension in string

\mu = mass / length

 

 


Option 1)

\frac{n}{3\sqrt3}

This is correct

Option 2)

3n

This is incorrect

Option 3)

\sqrt3 n

This is incorrect

Option 4)

\frac{n}{\sqrt3}

This is incorrect

Posted by

Aadil

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