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A particle has simple harmonic motion. The equation of its motion is x =5\sin(4t-\frac{\pi}{6}), where x is its displacement. If the displacement of the particle is 3 units, then its velocity is

  • Option 1)

    \frac{2\pi}{3}

  • Option 2)

    \frac{5\pi}{6}

  • Option 3)

    20

  • Option 4)

    16

 

Answers (1)

best_answer

From the given equation, a = 5 and \omega = 4

\therefore v = \omega\sqrt{a^{2}- y^{2}} = 4\sqrt{5^{2} - 3^{2}} = 16

 

Relation of velocity and displacement -

v= w\sqrt{A^{2}-x^{2}}
 

- wherein

\rightarrow  x is displacement from mean position

\rightarrow  A is Amplitude.

 

 

 


Option 1)

\frac{2\pi}{3}

This is incorrect.

Option 2)

\frac{5\pi}{6}

This is incorrect.

Option 3)

20

This is incorrect.This is incorrect.

Option 4)

16

This is correct.

Posted by

prateek

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