# When a mass M is attached to the spring of force constant K, then the spring stretches by $l$. If the mass oscillates with amplitude $l$, what will be the maximum potential energy stored in the spring Option 1) $\frac{Kl}{2}$ Option 2) $2Kl$ Option 3) $\frac{1}{2} Mgl$ Option 4) $Mgl$

D Divya Saini

$Mg = kl \Rightarrow U_{max} = \frac{1}{2}k(2l)^{2} = 2kl$

Option 1)

$\frac{Kl}{2}$

This is incorrect.

Option 2)

$2Kl$

This is correct.

Option 3)

$\frac{1}{2} Mgl$

This is incorrect.

Option 4)

$Mgl$

This is incorrect.

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