A particle of  mass m moves  along line  PC  with velocity \nu  as shown. What  is the angular momentum of the particle about  P?

Option 1)

m\nu L

Option 2)

m\nu l

Option 3)

m\nu r

Option 4)

zero

Answers (1)

As we learnt in

Angular momentum -

\vec{L}=\vec{r}\times \vec{p}

- wherein

\vec{L}  represent angular momentum of a moving particle about a point.

it can be calculated  as L=r_1\, P=r\, P_1

r_1 = Length of perpendicular on line of motion

P_1 = component of momentum along perpendicular to r

 

 The particle moves along the line PC.

\theta=0^{o}

L=mvr \; sin\theta^{o}

sin\;\theta^{o}=0

L = 0

 


Option 1)

m\nu L

This is an incorrect option.

Option 2)

m\nu l

This is an incorrect option.

Option 3)

m\nu r

This is an incorrect option.

Option 4)

zero

This is the correct option.

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