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  • Give answer! The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :

The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :

  • Option 1)

    0.529 Å

  • Option 2)

    2π×0.529 Å

  • Option 3)

    \frac{0.598}{2\pi} \AA

  • Option 4)

    4×0.529 Å

 

Answers (2)

best_answer

As we have learnt,

 

Bohr model and debroglie principle -

Bohr model,  mvr=\frac{nh}{2\pi}

Debroglie, p=\frac{h}{\lambda }

- wherein

Combining the two

2\pi r=n\lambda

 

 \lambda = \frac{h}{mv}, \;\; mvr = \frac{h}{2\pi} \Rightarrow 2\pi r = \frac{h}{mv} \\*\Rightarrow \lambda = 2\pi r = 2\pi \times 0.529 \AA  


Option 1)

0.529 Å

Option 2)

2π×0.529 Å

Option 3)

\frac{0.598}{2\pi} \AA

Option 4)

4×0.529 Å

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