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  • Give answer! - The electric field of a plane polarized electromagnetic wave in free space at time t = 0 is given b - Electromagnetic Waves - JEE Main

The electric field of a plane polarized electromagnetic wave in free space at time  t = 0 is given by an expression \vec{E}\left ( x,y \right )= 10 \hat{j}\cos \left [ \left ( 6x +8z\right ) \right ]

The magnetic field field \vec{B} \left ( x,z,t \right ) is given by :( c is the velocity of light)

 

  • Option 1)

    \frac{1}{c}\left ( 6\hat{k}-8\hat{i} \right )\cos \left [ \left ( 6x+8z-10ct \right ) \right ]

  • Option 2)

    \frac{1}{c}\left ( 6\hat{k}-8\hat{i} \right )\cos \left [ \left ( 6x+8z+10ct \right ) \right ]

  • Option 3)

    \frac{1}{c}\left ( 6\hat{k}+8\hat{i} \right )\cos \left [ \left ( 6x-8z+10ct \right ) \right ]

  • Option 4)

    \frac{1}{c}\left ( 6\hat{k}+8\hat{i} \right )\cos \left [ \left ( 6x+8z-10ct \right ) \right ]

Answers (1)

best_answer

 

Wave Equation -

E= E_{o} Sin w (t -\frac{x}{c})

E is in y-z plane

- wherein

E - Electric field at (x,t)

E0 - Electric field amplitude

\omega= Angular frequency

c= Speed of light in vacuum 

 

 

Wave Equation -

B=B_{o} Sinw (t-\frac{x}{c})

B is in y-z plane

- wherein

B = Magnetic field at (x,t)

B0 = Magnetic field amplitude

\omega = Angular frequency

c = Speed of light in vacuum

 

 

 


Option 1)

\frac{1}{c}\left ( 6\hat{k}-8\hat{i} \right )\cos \left [ \left ( 6x+8z-10ct \right ) \right ]

Option 2)

\frac{1}{c}\left ( 6\hat{k}-8\hat{i} \right )\cos \left [ \left ( 6x+8z+10ct \right ) \right ]

Option 3)

\frac{1}{c}\left ( 6\hat{k}+8\hat{i} \right )\cos \left [ \left ( 6x-8z+10ct \right ) \right ]

Option 4)

\frac{1}{c}\left ( 6\hat{k}+8\hat{i} \right )\cos \left [ \left ( 6x+8z-10ct \right ) \right ]

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