The number of 6 digit numbers that can be formed using the 

digits 0,1,2,5,7 and 9 which are divisible by 11 and no digit is repeated, is:

  • Option 1)

    72

  • Option 2)

    60

  • Option 3)

    48

  • Option 4)

    36

 

Answers (1)

Sum of the given digit is 0+1+2+5+7+9 = 24

6 digit number let abcdef 

abcdef is divisible by 11 if 

|(a+c+e)-(b+d+f)| is a multiple of 11 

Only one possible is there

a+c+e=b+d+f=12

Case 1: {a,c,e}={7,5,0}

             {b,d,f}={9,2,1}

 So, 2 x 2! x 3! = 24

Case 2: {a,c,e}={9 , 2, 1}

             {b,d,f}={7, 5, 0}

So, 3! x 3! = 36

Total = 24 + 36 = 60

So, correct option is (2).


Option 1)

72

Option 2)

60

Option 3)

48

Option 4)

36

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