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  • Give answer! The total length of a sonometer wire between fixed ends is 110 cm. Two bridges are placed to divide the length of wire in ratio 6 : 3 : 2. The tension in the wire is 400 N and the mass per unit length is 0.01 kg/m. What is the minimum co

The total length of a sonometer wire  between fixed ends is 110 cm. Two bridges are placed to divide the length of wire in ratio 6 : 3 : 2. The tension in the wire is 400 N and the mass per unit length is 0.01 kg/m. What is the minimum common frequency with which three parts can vibrate ?

 

  • Option 1)

    1100 Hz

  • Option 2)

    1000 Hz

  • Option 3)

    166 Hz

  • Option 4)

    100 Hz

 

Answers (1)

best_answer

Total length of sonometer wire l=110cm. = 1.1 m

length of wire is in ration, 6:3:2 v.e 60 cm., 30 cm., 20 cm

T=400N

w=0.01 kg

v=?

v=\frac{l}{2l}\sqrt{\frac{T}{w}}=\frac{1000}{11}Hz

v_{1}=\frac{1000}{6}Hz

v_{2}=\frac{1000}{3}Hz

v_{3}=\frac{1000}{2}Hz

hence common frequency = 1000Hz


Option 1)

1100 Hz

Incorrect Option

Option 2)

1000 Hz

Correct Option

Option 3)

166 Hz

Incorrect Option

Option 4)

100 Hz

Incorrect Option

Posted by

Aadil

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