The values of Van't Hoff factors for KCl, NaCl, and K2SO4 are 

  • Option 1)

    2,2,2

  • Option 2)

    2,2,3

  • Option 3)

    1,1,2

  • Option 4)

    1,1,1

 

Answers (1)
P Prateek Shrivastava

As we discussed in concept

Vant Hoff factor for dissociation -

i= 1+(n-1)\alpha

Where

n is the no. of dissociated particles

\alpha = degree of association
 

- wherein

NaC l \: \: \: n = 2

CaCl_{2} \: \: \: n = 3

K_{4}[F(CN_{6})]\: \: \: \: \: n=5

 

All strong electrolytes will dissociate completely

KCl\rightleftharpoons K^+ +Cl^-, Van't \: hoff\: factor =2

NaCl\rightleftharpoons Na^+ + Cl^-, Van't \: hoff\: factor =2 

K_2SO_4\rightleftharpoons 2K^+ +SO_4^{2-}, Van't \: hoff\: factor =3


Option 1)

2,2,2

Incorrect

Option 2)

2,2,3

Correct

Option 3)

1,1,2

Incorrect

Option 4)

1,1,1

Incorrect

Exams
Articles
Questions