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Given that standard heat enthalpy of CH4, C2H4 and C3H8 are -17.9, 12.5, -24.8 Kcal mol. The \delta H for CH4 + C2H4 \rightarrow C3H8 is:

  • Option 1)

    -55.2 Kcal mol-1

  • Option 2)

    -19.4 Kcal/mol

  • Option 3)

    -30.2 Kcal/mol

  • Option 4)

    55.2 Kcal/mol

 

Answers (1)

As learnt in

Heat of Reaction -

It is defined as the amount of  Enthalpy change in the reaction for given amount of reaction.

- wherein

C_{(s)}+O_{2(g)}\rightarrow CO_{2(g)}+393.5 KJ 

 

 \Delta H= -24.8-\left ( -17.9+12.5 \right )

            = -24.8+5.4

            = -19.4 Kcal mol-1


Option 1)

-55.2 Kcal mol-1

This option is incorrect

Option 2)

-19.4 Kcal/mol

This option is correct

Option 3)

-30.2 Kcal/mol

This option is incorrect

Option 4)

55.2 Kcal/mol

This option is incorrect

Posted by

Vakul

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