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  • Give answer! Two particles of displacements, one of magnitude 3m and another of magnitude 4m. Resultant amplitude/Disp is given by 7m. Find out theirphase difference

Two particles of displacements, one of magnitude 3m and another of magnitude 4m. Resultant amplitude/Disp is given by 7m. Find out their phase difference 

  • Option 1)

    0\degree

  • Option 2)

    180\degree

  • Option 3)

    90\degree

  • Option 4)

    45\degree

 

Answers (1)

best_answer

7 = \sqrt{3^{2} + 4^{2} +2\cdot 3\cos\theta} \\*\Rightarrow 49 = 9 + 16 + 24\cos\theta \\*\Rightarrow \cos\theta = 1 \Rightarrow \theta = 0\degree

 

Resultant phase of two superposing SHM's -

\phi '= \tan ^{-1}\left ( \frac{A_{2}\sin \phi }{A_{1}+A_{2}\cos \phi } \right )

A_{1}and A_{2}  are amplitudes of two SHM's. \phi is their phase difference.

- wherein

When two SHM's are along same direction and of same frequency.

 

 

 


Option 1)

0\degree

This is correct.

Option 2)

180\degree

This is incorrect.

Option 3)

90\degree

This is incorrect.

Option 4)

45\degree

This is incorrect.

Posted by

Avinash

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