Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Given below are two statements. Statement I: Iron (III) catalyst, acidified <img alt="\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}" src="/latex-image/?%5Cmathrm%7BK%7D_%7B2%7D%20%5Cmathrm%7

Given below are two statements.
Statement I: Iron (III) catalyst, acidified \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} and neutral \mathrm{KMnO}_{4} have the ability to oxidise \mathrm{I}^{-}$ to $\mathrm{I}_{2}  independently.
Statement II: Manganate ion is paramagnetic in nature and involves \mathrm{p \pi-p \pi} bonding.
In the light of the above statements, choose the correct answer from the options given below.
 

Option: 1

Both Statement I and Statement II are true.
 


Option: 2

Both Statement I and Statement II are false.
 


Option: 3

Statement I is true but Statement II is false.
 


Option: 4

Statement I is false but Statement II is true.


Answers (1)

best_answer

Iron (III) catalyst cannot oxidise \mathrm{I^{-}to\, I_{2}} independently.
Iron (III) catalyses the the reaction between iodide and persulphate ions.

\mathrm{2 \mathrm{I}^{-}+\mathrm{S}_2 \mathrm{O}_8^{2-} \rightarrow \mathrm{I}_2+2 \mathrm{SO}_4^{2-}}

Statement (1) is false
Manganate ion is paramagnetic in nature and involves \mathrm{p\pi -d\pi } bonding not \mathrm{p\pi -p\pi } bonding.
Statement II is false

Option (2) is correct.

Posted by

HARSH KANKARIA

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: NTA exam city intimation slip link available; admit card date
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads
anam-khan

Bihar Board extends BSEB Super 50 free coaching application last date to March 26

Latest Question