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Given below are two statements :
Statements I : If the number of turns in the coil of a moving coil galvanometer is doubled then the current
sensitivity becomes double.
Statements II : Increasing current sensitivity of a moving coil galvanometer by only increasing the number of
turns in the coil will also increase its voltage sensitivity in the same ratio
In the light of the above statements, choose the correct answer from the options given below :

Option: 1

Both Statement I and Statement II are true


Option: 2

Both Statement I and Statement II are false


Option: 3

Statement I is true but Statement II is false


Option: 4

Statement I is false but Statement II is true


Answers (1)

best_answer

\begin{aligned} & \mathrm{I}=\frac{\mathrm{k} \theta}{\mathrm{NBA}} \\ & \mathrm{C} \cdot \mathrm{S}=\frac{\theta}{\mathrm{I}}=\frac{\mathrm{NBA}}{\mathrm{K}} \\ & \mathrm{N} \rightarrow 2 \mathrm{~N} \quad \mathrm{C} \cdot \mathrm{S} \rightarrow 2 \mathrm{CS} \end{aligned}
But  \mathrm{VS} .=\frac{\theta}{\mathrm{V}}=\frac{\mathrm{NBA}}{\mathrm{KR}}
$$ \mathrm{N} \rightarrow 2 \mathrm{NC} \cdot \mathrm{S} \rightarrow 2 \mathrm{CS}
But  \mathrm{V}_{. S}=\frac{\theta}{\mathrm{V}}=\frac{\theta}{\mathrm{IR}}=\frac{\mathrm{NBA}}{\mathrm{RK}}
As  \mathrm{N} \rightarrow 2 \mathrm{~N}, \mathrm{R} \rightarrow 2 \mathrm{R} \text { So } \mathrm{V} . \mathrm{S}=\mathrm{constant}

Posted by

Irshad Anwar

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