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  • Gravitational field Intensity due to Uniform disc of radius 4 m at a distance of 3m from centre on its axis is (Take mass of disc as 5 kg and value of G as <span style="bac

Gravitational field Intensity due to Uniform disc of radius 4 m at a distance of 3m from centre on its axis is

(Take mass of disc as 5 kg and value of G as  6.67\times 10^{-11}\; N\: -m^{2})

Option: 1

6.67*10^{-11} \ m/s^2 
 


Option: 2

13.34*10^{-11} \ m/s^2  

 


Option: 3

3.335*10^{-11} \ m/s^2 


Option: 4

26.68*10^{-11} \ m/s^2 


Answers (1)

best_answer

As we learned

Gravitational field Intensity due to uniform disc -

For Uniform disc

 


 

\Theta \rightarrow Angle with axis

a \rightarrow Radius of disc

At the centre of the disc 

I=0

At a point on its axis

I=\frac{2GM}{a^{2}}\left ( 1-\cos \Theta \right )

From the figure, we can say that

r= 3m and a= 4m

SoCos\theta =\frac{3}{5}

So I=\frac{2GM}{a^{2}}\left ( 1-\cos \Theta \right )=\frac{2*6.67*10^{-11}*5}{4}(1-\frac{3}{5})=6.67*10^{-11}

Posted by

Rakesh

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