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Heating white phosphorus with conc. \mathrm{NaOH} solution gives mainly :

Option: 1

\mathrm{Na}_{3} \mathrm{P}$ and $\mathrm{H}_{2} \mathrm{O}


Option: 2

\mathrm{H}_{3} \mathrm{PO}$ and $\mathrm{NaH}


Option: 3

\mathrm{P}(\mathrm{OH})_{3}$ and $\mathrm{NaH}_{2} \mathrm{PO}_{4}


Option: 4

\mathrm{PH}_{3}$ and $\mathrm{NaH}_{2} \mathrm{PO}_{2}


Answers (1)

best_answer

As we have learnt, 

White Phosphorus disproportionates in alkali to form Phosphine and Hypophosphite.

The reaction is given as:

\mathrm{P}_{4}+3 \mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{PH}_{3}+3 \mathrm{NaH}_{2} \mathrm{PO}_{2}

Hence, the correct answer is Option (4)

Posted by

Ritika Jonwal

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