A 220 volt, 1000 watt bulb is connected across a 110 volt mains supply. The power consumed will be

  • Option 1)

    750 watt

  • Option 2)

    500 watt

  • Option 3)

    250 watt

  • Option 4)

    1000 watt.

 

Answers (3)

As we learnt in

Power dissipiated in the circuit -

P= \left (\frac{E}{R+\frac{r}{n}} \right )^{2}\cdot R         

-

 

 

 

 R = \frac{v^{2}}{P}= \frac{\left ( 220 \right )^{2}}{1000}= 48.4 \Omega

Required power = \frac{v^{2}}{R}= \frac{\left ( 110 \right )^{2}}{48.4}

= 250 w

 


Option 1)

750 watt

This option is incorrect.

Option 2)

500 watt

This option is incorrect.

Option 3)

250 watt

This option is correct.

Option 4)

1000 watt.

This option is incorrect.

why isin’t this possible P = V/I P1 = 1000W, P2=?, V1=220V,V2=110V

I=P1/V1=1000/220=4.55

P2=I*V2

P2=4.55*110

P2=500W

ANSWER (B)

why isin’t this possible

P = V/I

P1 = 1000W, P2=?, V1=220V,V2=110V

I=P1/V1=1000/220=4.55

P2=I*V2

P2=4.55*110

P2=500W

ANSWER (B)

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