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A 220 volt, 1000 watt bulb is connected across a 110 volt mains supply. The power consumed will be

  • Option 1)

    750 watt

  • Option 2)

    500 watt

  • Option 3)

    250 watt

  • Option 4)

    1000 watt.

 

Answers (3)

best_answer

As we learnt in

Power dissipiated in the circuit -

P= \left (\frac{E}{R+\frac{r}{n}} \right )^{2}\cdot R         

-

 

 

 

 R = \frac{v^{2}}{P}= \frac{\left ( 220 \right )^{2}}{1000}= 48.4 \Omega

Required power = \frac{v^{2}}{R}= \frac{\left ( 110 \right )^{2}}{48.4}

= 250 w

 


Option 1)

750 watt

This option is incorrect.

Option 2)

500 watt

This option is incorrect.

Option 3)

250 watt

This option is correct.

Option 4)

1000 watt.

This option is incorrect.

Posted by

divya.saini

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why isin’t this possible P = V/I P1 = 1000W, P2=?, V1=220V,V2=110V

I=P1/V1=1000/220=4.55

P2=I*V2

P2=4.55*110

P2=500W

ANSWER (B)

Posted by

KRISHNAMOORTHY

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why isin’t this possible

P = V/I

P1 = 1000W, P2=?, V1=220V,V2=110V

I=P1/V1=1000/220=4.55

P2=I*V2

P2=4.55*110

P2=500W

ANSWER (B)

Posted by

KRISHNAMOORTHY

View full answer